In the first pic (green circle), the lead of the 1.8K resistor attached to the rectifier tube socket should be moved over to the filter cap terminal on the other end of the jumper. Then replace the jumper with the new resistor to be determined. Adding this resistor reduces the B+ voltages down to the specified voltage at C45A. By dropping the voltage to this first filter cap section, all the rest of the B+ voltages will then fall in line appropriately.
The installation of the 1Ω resistor is correct as described. However, I forgot about the heater of V4 also operating from the AC heater winding, so it should actually be a .5Ω 2 watt resistor (two 1Ω resistors in parallel). By adding this resistance into the circuit, the voltage to the AC powered heaters and the indicator lamps will then be very nearly 6.3 vac, rather than the 7 volts you indicated they were receiving.
The voltage level to the tube heaters powered by DC is correct, so lowering the B+ and AC heater voltage by adjusting the voltage to the primary winding of the transformer would then leave the voltage to the DC powered heaters too low. Therefore, the B+ and AC powered heater voltages are each adjusted individually, allowing the B+, AC heater voltage, and DC heater voltage to be correct.
I hope that helps!
Dave